11x^2-23x+2=0

Solution for 11x^2-23x+2=0 equation:

11x^2-23x+2=0

a = 11; b = -23; c = +2;
Δ = b2-4ac
Δ = -232-4·11·2
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-21}{2*11}=\frac{2}{22}
=1/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+21}{2*11}=\frac{44}{22}
=2
$